- As usual Mr.Backe asked us if we needed help on a question. Then Elijah answered yes. So together we solved #17 from 6.1 in our textbooks.
a) Make a table of values for the first five rebound heights of the previous one. (First look at what we already know. I highlighted them.) What we did was draw a picture and worked from there using a T-chart. *P.s i can't draw the picture right now, but ill try doing the chart.
B | 0, 1 , 2, 3, 4, 5 Remember that we start with 0 because the ball was just dropped and bounced.
# cm | 2m, 413m, 819m, 16/27m, 32/81m, 64/43m We got those numbers by multiplying the previous bounce height by 2/3 because "of" means multiplying.
2/3 x 2/1 = 4/3m
2.3 x 4/3 = 8/9m
2/3 x 8/9= 16/27m
2/3 x 16/27 = 32/81m
2/3 x 32/81 = 64/243m
b) What is the height of the fourth rebound bounce?
c) Is this a linear relation?
No. I know this because if we were to graph it it would show a curve if we lined the dots. That means its not a linear relation. Why? Because when we draw lines connecting dots, in linear relations it would be a straight line.
- We learned how to extrapolate and interpolate.
Interpolate : Looking for a missing value inside the given data.
- By the end of the class we learned 3 ways to solve linear relations by graph, formula, and inspection.