## Thursday, January 27, 2011

### Jem's blog for January 26. 2011

Goodmorning classmates! Now is the time to go back to yesterdays math class. Let's go over what we did and learned yesterday.

1. As usual Mr.Backe asked us if we needed help on a question. Then Elijah answered yes. So together we solved #17 from 6.1 in our textbooks.
Question: A ball dropped from a height of 2m. The ball rebounds to 2/3 of the height it was dropped from. Each subsequent rebound is 2/3 of the height of the previous one.

a) Make a table of values for the first five rebound heights of the previous one. (First look at what we already know. I highlighted them.) What we did was draw a picture and worked from there using a T-chart. *P.s i can't draw the picture right now, but ill try doing the chart.

B | 0, 1 , 2, 3, 4, 5 Remember that we start with 0 because the ball was just dropped and bounced.
# cm | 2m, 413m, 819m, 16/27m, 32/81m, 64/43m We got those numbers by multiplying the previous bounce height by 2/3 because "of" means multiplying.

2/3 x 2/1 = 4/3m
2.3 x 4/3 = 8/9m
2/3 x 8/9= 16/27m
2/3 x 16/27 = 32/81m
2/3 x 32/81 = 64/243m

b) What is the height of the fourth rebound bounce?
32/81m

c) Is this a linear relation?
No. I know this because if we were to graph it it would show a curve if we lined the dots. That means its not a linear relation. Why? Because when we draw lines connecting dots, in linear relations it would be a straight line.

1. We learned how to extrapolate and interpolate.
Extrapolate: Looking for a missing value outside the given data
Interpolate : Looking for a missing value inside the given data.

1. By the end of the class we learned 3 ways to solve linear relations by graph, formula, and inspection.
DO YOUR HOMEWORK GUYS! I dont know who hasn't done the blog yet so ill just tell ya guys later.