Mary Jane's Scribepost for March 21, 2011

In today's math class we were given back our Equations Test. We went over the test and Mr. Backe also gave us some more equations to solve.

Test Questions:

Equations:

For some of the equations, we had to find the common denominator and the lowest common multiple.

We also have another equation test coming up on Wednesday.

That's all we did today. THANK YOU FOR READING AND PLEASE COMMENT !

Allysa's Blogpost for March 8, 2011

Our class today, involved the beginning of Chapter 8.
It started off with this:Next, we went over some of the textbook questions on 8.1 that we didn't understand.










CLICK TO ENLARGE IMAGES.

STASH IT CHAPTER 7:
- Self Assessment
- Problem of the Week
- Polynomial Puzzle Sheet

HOMEWORK:
- All the textbook questions in 8.1 & 8.2
- 8.1 & 8.2 Homework Book

Thanks for reading my blog! Before you go, please leave a comment!

Noelle's Blog Post for Feb. 28th, 2011

What did we learn today?

Turning a trinomial into a binomial:

Trinomial ---> Binomial

How do you do it?

To get from a trinomial to binomial you have to find the product of each term and seperate them into the two terms of a binomial.

Here's the tricky part; The constants in your binomials must add up to the constant or coefficient in the middle term, but multiply to get the constant or coefficient in the last term of the trinomial.

Make sense? Here are a couple examples to show how it works:

x^2 + 7x - 18 --->Binomial

(x+9)(x-2) = Binomial

(+9)(-2)=(-18)

9+(-2)=7

y^4 - 3x - 18 --->Binomial

(y^2-6)(y^2+3)

(-6)(3)=(-18)

(-6)+3=(-3)

This is what we learnt, and then we played TUTPUP!

Aight, that was basically all we learned. I choose EMMANUEL to do the next blog post because he didn't do it on thursday.

Brayden's Blog Post for February 16,2011

Today in class we continued to learn about multiplying polynomials.







Ex.


2x(3x+7) = (2 x 3 x) + ( 2 x 7 ) This is called distributive property.


= (2 3 x x) + (2 7 x) You then put the like terms together.


= 6x^2 + 14x Then you simply multiply the terms to get your answer.





Here is another example of multiplying polynomials





-2x(3x+2y-1) = ( -2 x 3 x ) + ( -2 x 2 y) + ( -2 x -1)


= ( -2 3 x x ) + ( -2 2 x y ) + ( -2 -1 x )


= -6x^2 +( -4xy) + 2x


= -6x^2 -4xy + 2x








After that the teacher showed us how to model equations.



This equation is 3x (2x+1)



The lone number is the number you multiply by and the 2 numbers are the numbers being multiplied.


This is our homework.
Read Pages 264-268
CYU 2+3
Practice Odd + Evens
Any 2 Apply
Extend 19+20 or 20+21
Homework book 7.2
Extra Practice 7.2


EMMANUEL is doing the next blog

Darnell's Blog Post for February 14, 2011.

Hello class. Today we learned more about the information on chapter 7 monomials.

First we learned about Distributive Property.

It's a process where you distribute the negative one (monomial) over the binomial.

Example:

-(6x+7) = -1 (6x) + (-1) (7)

= -6x-7

The negative turns into a -1.

We did some questions and did both pictures and work in class.

You can tell the answer is right

in the picture if the first factor ( the left side ) and the second factor ( the top side ) are matched up with the shape thats in the middle of the graph.

Next we tried it with fractions. In this case we had something that helped. Anything over itself for example like 12/12 or X/X, the answer is 1.

For homework we have:

7.1 Extra Practice

7.1 Homework Book

7.1 254-259 CYU 1 & 2

Practice odd or even

Apply All

Extend

7.10 Monomial Division

Binesi's Blog for January 28th 2011

Today in Class we took some notes.

I was half awake and on the verge of collapsing, so I didn't quite get all of the information. I borrowed Hannah's notes so I figure about half of this scribe is accredited to her.

Due Sunday-

For homework we have to do a Power Point Presentation. Put an example, non example, picture, and a definition.

Interpolate

Extrapolate

Negative Line

Positive Line

Dependant

& Independent

We also have to do 6.3 CYU #2, either the odd or even for practice, Apply (any 3), and extend any 2.

6.3 Extra Practice, and the workbook.

Jem's blog for January 26. 2011

Goodmorning classmates! Now is the time to go back to yesterdays math class. Let's go over what we did and learned yesterday.

1. As usual Mr.Backe asked us if we needed help on a question. Then Elijah answered yes. So together we solved #17 from 6.1 in our textbooks.

Question: A ball dropped from a height of 2m. The ball rebounds to 2/3 of the height it was dropped from. Each subsequent rebound is 2/3 of the height of the previous one.

a) Make a table of values for the first five rebound heights of the previous one. (First look at what we already know. I highlighted them.) What we did was draw a picture and worked from there using a T-chart. *P.s i can't draw the picture right now, but ill try doing the chart.

B | 0, 1 , 2, 3, 4, 5 Remember that we start with 0 because the ball was just dropped and bounced.
# cm | 2m, 413m, 819m, 16/27m, 32/81m, 64/43m We got those numbers by multiplying the previous bounce height by 2/3 because "of" means multiplying.

2/3 x 2/1 = 4/3m
2.3 x 4/3 = 8/9m
2/3 x 8/9= 16/27m
2/3 x 16/27 = 32/81m
2/3 x 32/81 = 64/243m

b) What is the height of the fourth rebound bounce?
32/81m

c) Is this a linear relation?
No. I know this because if we were to graph it it would show a curve if we lined the dots. That means its not a linear relation. Why? Because when we draw lines connecting dots, in linear relations it would be a straight line.

1. We learned how to extrapolate and interpolate.

Extrapolate: Looking for a missing value outside the given data
Interpolate : Looking for a missing value inside the given data.

1. By the end of the class we learned 3 ways to solve linear relations by graph, formula, and inspection.

DO YOUR HOMEWORK GUYS! I dont know who hasn't done the blog yet so ill just tell ya guys later.